Hey everyone!
I would like to start off by reminding everyone there will be a test on friday and our exam begins on tuesday in class! You only need to bring writing devices and a calculator to the exam, do not bring your books and papers! :D
Okay so we began todays class with a demonstration about Lens law. We saw that a magnet dropped down a copper tube took longer to fall then a regular piece of metal.
Next we went through a worksheet called Electromagnetic Induction (Lenz's Law)
The answers are...
1. Left side: N Right side: S Current: up
2. Left side: S Right Side N Current: down
3. Left side: S Right Side: N Current: down
4. Left side: S Right side: N Current down
5. Left side: S Right side: N Current down
6. Left side: N Right side: S Current: up
7. Left side: N Right side: S Current up
8. no current.
We then corrected the Transformers worksheet.
1. 1200v
2. 1.2A
3. 1440W
4. 1440 W
5. 12A
6.up, down
7. more, less
8. voltage, energy and power
9. step down, 20/1
10. ac, continually change
Lastly we corrected the chapter 26 review. We did not have to do questions 4 and 5.
1. 5.0 x 10^-4 v
2. 2.24x10^-5A
3. down
6. Left side: s Right side: N Current: up
7. 125:1
8. a)300 000 b) 1: 2 500
9. a) 3 x 10^5 b) 0.06A c) 18 000 W
The next few days of class will be used for asking questions about the exam and test. Have fun studying!
Showing posts with label Rebecca. Show all posts
Showing posts with label Rebecca. Show all posts
Wednesday, June 9, 2010
Sunday, February 21, 2010
Scribe for the 19th
Hey everyone, I hope you're having a good weekend.
So on Friday we started off by going over the 4 questions at the end of the dynamics unit booklet. So here is an explanation of the answers (they can also be found on the previous slide if my explanation doesn't make sense.)
1.a) No it can't be at equilibrium because the object will accelerate according to Newtons second law (A body will accelerate with acceleration proportional to the force and inversely proportional to the mass)
b) An example of something that is mutually perpendicular is an arrow pointing up and an arrow pointing to the left. This could not be at equilibrium as the sum of the two arrows would not equal zero.
c) An object acted upon by two not mutually perpendicular forces may be at equilibrium IF the forces look like this <---.---> This is an example of equilibrium because the sum of the forces would equal zero. However not mutually perpendicular forces aren't always at equilibrium. If the sum of the forces is not equal to zero (an arrow pointing northeast and an arrow pointing south) then they object acted upon is not at equilibrium.
2. To answer this question we must use the formula 2Ft- Fg= 0
Which we rearrange to become 2Ft= Fg
Fg is equal to mass times gravity so we can rewrite it like this, 2Ft= mg
Now plug in your values. 2Ft= (12.0kg)(9.8N/Kg)
Ft= 58.8N
3. The free body diagram for this question is (Ft) <------. ------> (Fa)
We use the formula -Ft + Fa= 0
Which can be rearranged to become -Ft= - Fa
We know that Fa = 35 N which means that Ft also equals 35 N
We are trying to solve for mass so we will write Ft= mg
m= 35N/(9.8 N/Kg)
m= 3.6 Kg
4. For this question we were trying to find the y component of the vector. (that would be the green arrow in the diagram on the previous slide) These green arrows represent the force of the tension in the wire, this force must be equal to the Fg otherwise she would not be at equilibrium. We used sine to solve for the y value because we knew one angle, remember Sin= opposite / hypotenuse.
We then corrected the Net Force worksheet. Here are the answers.
We then got a worksheet with 5 questions about dynamics. It would probably be wise to do this worksheet since I believe we are correcting it tomorrow. (:
Next scribe will beee Wahida.
So on Friday we started off by going over the 4 questions at the end of the dynamics unit booklet. So here is an explanation of the answers (they can also be found on the previous slide if my explanation doesn't make sense.)
1.a) No it can't be at equilibrium because the object will accelerate according to Newtons second law (A body will accelerate with acceleration proportional to the force and inversely proportional to the mass)
b) An example of something that is mutually perpendicular is an arrow pointing up and an arrow pointing to the left. This could not be at equilibrium as the sum of the two arrows would not equal zero.
c) An object acted upon by two not mutually perpendicular forces may be at equilibrium IF the forces look like this <---.---> This is an example of equilibrium because the sum of the forces would equal zero. However not mutually perpendicular forces aren't always at equilibrium. If the sum of the forces is not equal to zero (an arrow pointing northeast and an arrow pointing south) then they object acted upon is not at equilibrium.
2. To answer this question we must use the formula 2Ft- Fg= 0
Which we rearrange to become 2Ft= Fg
Fg is equal to mass times gravity so we can rewrite it like this, 2Ft= mg
Now plug in your values. 2Ft= (12.0kg)(9.8N/Kg)
Ft= 58.8N
3. The free body diagram for this question is (Ft) <------. ------> (Fa)
We use the formula -Ft + Fa= 0
Which can be rearranged to become -Ft= - Fa
We know that Fa = 35 N which means that Ft also equals 35 N
We are trying to solve for mass so we will write Ft= mg
m= 35N/(9.8 N/Kg)
m= 3.6 Kg
4. For this question we were trying to find the y component of the vector. (that would be the green arrow in the diagram on the previous slide) These green arrows represent the force of the tension in the wire, this force must be equal to the Fg otherwise she would not be at equilibrium. We used sine to solve for the y value because we knew one angle, remember Sin= opposite / hypotenuse.
We then corrected the Net Force worksheet. Here are the answers.
We then got a worksheet with 5 questions about dynamics. It would probably be wise to do this worksheet since I believe we are correcting it tomorrow. (:Next scribe will beee Wahida.
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